9x^2-16x-33=0

Solution for 9x^2-16x-33=0 equation:

9x^2-16x-33=0

a = 9; b = -16; c = -33;
Δ = b2-4ac
Δ = -162-4·9·(-33)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-38}{2*9}=\frac{-22}{18}
=-1+2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+38}{2*9}=\frac{54}{18}
=3
$